Question

find a quadratic polynomial the sum and product of whose zeroes are (-3) and 2 respectively

Answer 1

Alpha=(-3) bita=2
-b/a = 3/1
c/a = 2/1 ( put these values in ax2+bx+c eqn)
X*2+3x+2 is the quadratic eqn

Answer 2

Howdy!!

your answer is ---

let,
$\alpha \: and \: \beta$
be the zeroes of the requited polynomial

Given
$\alpha + \beta = - 3$

&
$\alpha \beta = 2$

We know that,
the required polynomial
=

${x}^{2} - ( \alpha + \beta )x + \alpha \beta$

now , put the given value,
then , the required polynomial is
${x}^{2} - ( - 3)x + 2 \\ = {x}^{2} + 3x + 2$

hope it help you