Find a quadratic polynomial, the sum, and product of whose zeroes are 7/3 and -2 respectively.
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Answered by
1
Answer:
Given that,
Sum of the zeroes = 7/3
.i. e., alpha + beta = 7/3
Product of zeroes = -2
i. e., alpha × beta = -2
Then the polynomial is of the form,
x² - (alpha + beta) × x + ( alpha × beta ) = 0
x² - 7/3 × x + (-2) = 0
x² - 7x/3 - 2 = 0
3x² - 7x - 6/3 = 0
3x² - 7x - 6
Then the polynomial is 3x² - 7x - 6
Answered by
0
Answer:
Given = sum of roots = 7/3
Product of roots = -2
Let \alpha and \beta be the two zeroes of the quadratic polynomial.
We know that,
{x}^2- (sum of roots)x + (product of roots)
{x}^2 -7/3x + -2
Hence, {x}^2 -7/3x + -2 is the required quadratic equation
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