Question

Find a quadratic polynomial, the

sum and product of whose zeroes

are √2 and -3/2 respectively?

pls help​

Answer 1

Answer:

${\huge{\bold{\purple{\underline{Answer :-}}}}}$

Given

• The sum and product of whose zeros are √2 and -32.

Solution:

Let's

• Sum of zeros (S)
• Product of zeros (P)

A/Q.

• Sum aap zeros = √2
• Product of zeros = -32

We have Fromula.

=> K(x2-Sx+P)

• K Constant terms.
• S Sum of zeros.
• P Product of zeros.
• Putting given value in it.

=> K[x2-√2 2x -32].

Therefore, the our quadratic polynomial become x2-√2x -32.

Answer 2

Step-by-step explanation:

We know that every quadratic equation is based on this relation..

p(x) = kx² - (α+β)x + αβ

 where, α and β are the zeroes of given polynomial.

Now putting values of (α+β)and  αβ in above equation, we get ...

p (x) = x² - (√2)x + (-3/2) = 0

x² - √2x - 3/2 = 0

Let us multiply both sides by 2, we get...

2x² - 2√2x -3 = 0

Hence, the required polynomial is 2x² - 2√2x -3.

I hope it's help you.☺