find a quadratic polynomial the sum and product of whose zeros are -3 and 2 respectively.
Answers
Answered by
10
let a=-3 and b= 2
then a+ b=-3+2=-1
and a×b=-3×2=-6
we are knowing that
p(x)=x2 -(a+b)x+a×b
=x2-(-1)x+(-6)
=x2+1x-6 answer
then a+ b=-3+2=-1
and a×b=-3×2=-6
we are knowing that
p(x)=x2 -(a+b)x+a×b
=x2-(-1)x+(-6)
=x2+1x-6 answer
Answered by
9
Hey friend, here is your answer
alpha + beta= -3
alpha× beta= 2
( My keyboard doesn't have alpha and beta signs so I am writing them as alpha and beta)
Quadratic equation
= X^2 - (alpha + beta) X + alpha × beta
=> X^2 - ( -3) X + (2)
=> X^2 + 3X + 2 is our required quadratic equation
I HOPE IT HELPS. PLEASE MARK AS BRAINLIEST
alpha + beta= -3
alpha× beta= 2
( My keyboard doesn't have alpha and beta signs so I am writing them as alpha and beta)
Quadratic equation
= X^2 - (alpha + beta) X + alpha × beta
=> X^2 - ( -3) X + (2)
=> X^2 + 3X + 2 is our required quadratic equation
I HOPE IT HELPS. PLEASE MARK AS BRAINLIEST
MohammadTauheed:
your answer is wrong here we have two zeros not their their sum amd product
first we have to find their sum and product
First read the question carefully. We have sum and product of zeroes not the zeroes.
first you read the question carefully ok
ya sorry
My answer is right. READ THE QUESTION FIRST
sorry
you are correct
No problem Bro
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