Find a quadratic polynomial the sum and product of whose zeroes are 6 and 9 respectly find the zeroes
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Hey buddy here is ur answer ..
→ alpha = 6
→ beta = 9
Now ,
》x^2 + (alpha)x + (beta)
》x^2 + 6x + 9
Hence ,
》a = 1 , b = 6 , c = 9
→ For Quadratic polynomial
ax^2 + bx + c
》alpha + beta = - b /a
-6/1 = -6
》alpha × beta = c/a
9/1 = 9
HoPe U LiKe AnSwEr
...........(^_^)...........
BE BRAINLY
→ alpha = 6
→ beta = 9
Now ,
》x^2 + (alpha)x + (beta)
》x^2 + 6x + 9
Hence ,
》a = 1 , b = 6 , c = 9
→ For Quadratic polynomial
ax^2 + bx + c
》alpha + beta = - b /a
-6/1 = -6
》alpha × beta = c/a
9/1 = 9
HoPe U LiKe AnSwEr
...........(^_^)...........
BE BRAINLY
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