Find a quadratic polynomial the sum and the product of whose zeroes are -3 and 2 respectively
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Answered by
0
TWO ZEROES ARE,
Alpha=-3 and Beta=2
alpha + beta=-b/a
-3+2=-b/a
-1=-b/a
alpha*beta=c/a
-3*2=c/a
-6=c/a
x^2+x-6 is the polynomial
Alpha=-3 and Beta=2
alpha + beta=-b/a
-3+2=-b/a
-1=-b/a
alpha*beta=c/a
-3*2=c/a
-6=c/a
x^2+x-6 is the polynomial
Pavis:
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sorry there is a slight error in my answer
oh sorry its correct
It's wrong.
Answered by
3
Let alfa + beta = -3
and, alfa*beta = 2
Now,
quadratic polyno. = x^2 - (alfa + beta)x + alfa*beta
=> Quadratic polynomial = x^2 - (-3)x + 2
=> Quadratic polynomial =
x^2 +3x +2.
and, alfa*beta = 2
Now,
quadratic polyno. = x^2 - (alfa + beta)x + alfa*beta
=> Quadratic polynomial = x^2 - (-3)x + 2
=> Quadratic polynomial =
x^2 +3x +2.
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I think u have to verify your answer
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