Question

find a quadratic polynomial the sum of product of whose zeros are 0 and -4/3 respectively hence find the zeros

Answer 1

Hey friend here's your answer ***********************************************************Sum of the zeroes of a quadratic polynomial
=(-b)/a
Product of zeroes of a quadratic polynomial
=c/a

So...
0=(-b)/a

Which shows that 'b' is 0
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(-4)/3 = c/a

Which shows that 'c' is (-4)

& 'a' is 3
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Hence the polynomial is

= 3X^2 + 0 +(-4)

= 3X^2 - 4
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HOPE IT HELPS YOU

Answer 2

Answer:

Step-by-step explanation:

Quadratic Polynomial

=x2-(sum of zeroes)x + product of zeroes

=x2-(0)x +(-3/5)=x2 - 3/5

=x2 - (root3/5)2

=(x-root3/5)(x+root3/5)=0

X=root3/5*5/5 or x=-root3/5*5/5

X=root15/5 or x=-root15/5