Question

Find a quadratic polynomial the sum of whose zeroes is -3 and product of zeroes is 2​ Respectively

Answer 1

plz unfoll.ow me dear

Correct Question :-

The circumference of the base of a cylindrical vessel is 88 cm and it's height is 22 cm. Find the capacity of the cylindrical vessel. (Take, π = 22/7).

Given :-

The circumference of the base of a cylindrical vessel is 88 cm and it's height is 22 cm.

To Find :-

What is the capacity of the cylindrical vessel.

Formula Used :-

$\clubsuit$ Circumference of a Circle :

$\longmapsto \sf\boxed{\bold{\pink{Circumference\: of\: Circle =\: 2{\pi}r}}}$

$\clubsuit$ Volume of Cylinder :

$\longmapsto\sf\boxed{\bold{\pink{Volume\: of\: Cylinder =\: {\pi}{r}^{2}h}}}$

where,

r = Radius

h = Height

Solution :-

First, we have to find radius of a circle :

Given :

Circumference = 88 cm

π = 22/7

According to the question by using the formula we get,

$\implies \sf 2 \times \dfrac{22}{7} \times r =\: 88$

$\implies \sf \dfrac{44}{7} \times r =\: 88$

$\implies \sf r =\: 88 \times \dfrac{7}{44}$

$\implies \sf r =\: \dfrac{88 \times 7}{44}$

$\implies \sf r =\: \dfrac{\cancel{616}}{\cancel{44}}$

$\implies \sf\bold{\green{r =\: 14\: cm}}$

Hence, the radius of a circle is 14 cm.

Now, we have to find the capacity of the cylindrical vessel :

Given :

Radius = 14 cm

Height = 22 cm

π = 22/7

According to the question by using the formula we get,

$\implies \sf Capacity\: of\: cylindrical\: vessel =\: \dfrac{22}{7} \times {(14)}^{2} \times 22$

$\implies \sf Capacity\: of\: cylindrical\: vessel =\: \dfrac{22}{7} \times 196 \times 22$

$\implies \sf Capacity\: of\: cylindrical\: vessel =\: \dfrac{22}{\cancel{7}} \times {\cancel{4312}}$

$\implies \sf Capacity\: of\: cylindrical\: vessel =\: 22 \times 616$

$\implies \sf\bold{\red{Capacity\: of\: cylindrical\: vessel =\: 13552\: {cm}^{3}}}$

$\therefore$ The capacity of the cylindrical vessel is 13552 cm³.