Question

find a quadratic polynomial the sum of zeroes is 4 and one zero is 5

Answer 1

$product \: of \: zeros = 4 \times 5 = 20 \\ quadratic \: polynomial = {x}^{2} - (su m \: of \: zeros)x + (product \: of \: zeros) = 0 \\ {x}^{2} - (4)x + 5 = 0\\ {x}^{2} - 4x + 5 = 0$
Heyy friend your answer is here

Answer 2

Answer:

$x^{2} -4x-5=0$

Step-by-step explanation:

Given: Sum of zeroes$=4,$ one zero is$=5.$

To find: Quadratic polynomial.

Let two zeros be $\alpha ,\beta$.

$\alpha +\beta =4\\5+\beta =4\\\beta =-1$

We know that quadratic equation is given by:

$x^{2} -(\alpha +\beta )x+\alpha \beta$

So, the quadratic equation is:

$x^{2} -4x-5=0$