Find a quadratic polynomial where sum and product of the zeroes are 21/8 & 5/16 respectively
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let us assume the two zeroes to be x and y.
x + y= -b/a xy= c/a
= 21/8 =5/16
=42/16
Therefore,
a=16, b=-42, c=5
polynomial= ax^2 + bx + c
p(x) = 16x^2 -42x + 5
pls mark it as the brainliest ans
x + y= -b/a xy= c/a
= 21/8 =5/16
=42/16
Therefore,
a=16, b=-42, c=5
polynomial= ax^2 + bx + c
p(x) = 16x^2 -42x + 5
pls mark it as the brainliest ans
shrutisuresh:
can you explain how you got 42/16
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