Question

find a quadratic polynomial whose alpha,beta are minus 2 , 1 by 3

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Answer 1

Answer:

Sol : Let α and ß be the zeroes of p ( x ).

A/Q,

α + ß = 3 ------- equation 1

α - ß = - 1 ------- equation 2

By adding equation 1 and 2,

α + ß + α - ß = 3 - 1

2 α = 2

α = 2 / 2 = 1.

By substituting the value of α in equation 1,

α + ß = 3

1 + ß = 3

ß = 3 - 1

ß = 2

Now by multiplying α and ß,

α * ß = 2 * 1 = 2.

The formula for a quadratic equation ,

= x² - ( α + ß ) x + α * ß

By substituting the values of ( α + ß ) and α * ß ,

= x² - ( 3 ) x + 2

= x² - 3 x + 2.

So , your answer is ( x² - 3 x + 2 ).

Answer 2

Answer:

This is your ans. Hope it helps ..