Find a quadratic polynomial whose one of the zeroes is -15 and sum of the zeroes is 42.
Answers
Answered by
6
Hi friend !!
======================
let other zero be x
x-15= 42
x = 42+15
x = 57
the product of zeroes is 57×-15 = -855
the quadratic polynomial
x²-(sum of zeroes)x+product of zeroes
= x²-42x+-855
= x²- 42x - 855
♡♥hope it helps u♥♡
======================
let other zero be x
x-15= 42
x = 42+15
x = 57
the product of zeroes is 57×-15 = -855
the quadratic polynomial
x²-(sum of zeroes)x+product of zeroes
= x²-42x+-855
= x²- 42x - 855
♡♥hope it helps u♥♡
piryagor:
sorry. there is some mistake
Answered by
5
HELLO.......FRIEND!!
THE ANSWER IS HERE,
One of the zero => -15.
Let the other zero be x.
So, From the question,
=> x-15 = 42
=> x=42+15
=> 57.
Product of zeroes=> 57 ×(-15)
=> -855
Quadratic equation,
![= > \: {x}^{2} - (sum \: of \: zeroes)x + product \: of \: zeroes = > \: {x}^{2} - (sum \: of \: zeroes)x + product \: of \: zeroes](https://tex.z-dn.net/?f=+%3D++%26gt%3B++%5C%3A++%7Bx%7D%5E%7B2%7D++-+%28sum+%5C%3A+of+%5C%3A+zeroes%29x+%2B+product+%5C%3A+of+%5C%3A+zeroes)
![= > \: {x}^{2} - 42x - 855 = > \: {x}^{2} - 42x - 855](https://tex.z-dn.net/?f=+%3D++%26gt%3B++%5C%3A++%7Bx%7D%5E%7B2%7D++-+42x++-+855)
:-)Hope it helps u.
THE ANSWER IS HERE,
One of the zero => -15.
Let the other zero be x.
So, From the question,
=> x-15 = 42
=> x=42+15
=> 57.
Product of zeroes=> 57 ×(-15)
=> -855
Quadratic equation,
:-)Hope it helps u.
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