Question

Find a quadratic polynomial whose one zero is 6 and product of zeros is-18

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

k [ $x^{2}$ - 3x -18]

Step-by-step explanation:

One zero = 6 (α)    

Let another zero = β

Product of zeroes = -18

α * β = -18

6 *  β = -18

β = -3

Sum of zeroes = α + β

                        = 6 + (-3)

                        = 3

Quadratic polynomial =

k [$x^{2}$ - (α + β)x + α * β ]

k [ $x^{2}$ - 3x -18]

K is an constant here

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