Question

Find a quadratic polynomial whose one zero is 8 and sum of its zero is -14...
please help me this question I will definitely mark ur answer as brainliest...

Answer 1

Solution :

We have,

$\tt \blacksquare \: Sum \: of \: Zeros \\ \tt \alpha + \beta = \frac{ - b}{a}$

$\tt \blacksquare \: product\: of \: Zeros \\ \tt \alpha \beta = \frac{ c}{a}$

Let's One of it's Zeros be alpha.

• alpha = 8.

A/Q,

$\tt \longmapsto \alpha + \beta = - 14.$

$\tt \longmapsto 8 + \beta = - 14.$

$\tt \longmapsto \beta = - 14 - 8.$

$\tt\longmapsto \beta = - 22.$

Now,

• Sum of Zeros.
• -14.

$\rule{90}1$

• Product of zeros.
• -176.

$\rule{90}1$

We have, Formula.

K( x² - Sx + P )

Where as,

• K ( Constant term )
• S ( Sum of zeros )
• P ( Product of zeros )

=> k [ x² - ( - 14 )x - 176 ]

=> k [ x² + 14x - 176 ]

$\rule{90}1$

Therefore, the Our Quadratic polynomial is x² + 14x - 176.