Question

find a quadratic polynomial whose sum and product of its zeros are -8/3 and 4/3 ​

Answer 1

Answer:

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Step-by-step explanation:

x^2 + (a + b ) x - ab           .....is the equation

... putting zeros

x^2 + (-8/3)x  - 4/3

x^2 - 8/3 - 4/3 =0

3x^2 -8 -4 =0 is the required eq

Answer 2

answer

3x^ + 8x + 4

step by step explanation:

given:

the sum and the product of the zeroes of a quadratic equation is -8/3 and 4/3 respectively

to find:

the quadratic equation of the given information

solution:

the general form of a quadratic equation is

k{x^2 - (a + b)x + ab},where k is 1

and a, b are zeroes of the equation

by putting the values of the sum and product of zeroes

we get,

=> x^2 + 8/3x + 4/3

=> 3x^2 + 8x + 4

therefore, the required quadratic equation with sum and product of zeroes given is 3x^2 + 8x + 4.