Question

Find a quadratic polynomial whose sum and product of its zeroes are respectively 13 and 12.​

Answer 1

Answer:

x²-13x+12=0

Step-by-step explanation:

Given -b/a = 13 c/a =12

taking a = 1

we get b = -13 and c = 12

So the polynomial is 1.x² - 13.x + 12 = 0

Thank You.

Hopefully u appreciate my work and mark this as Brainliest

Kindly Follow.

Answer 2

Step-by-step explanation:

Question :-

Find a quadratic polynomial whose sum and product of its zeroes are respectively 13 and 12.

Answer :-

Given :

• The sum of zeros = 13
• The product of zeros = 12

Formula being used :

Required Quadratic polynomial is,

${\large{\bf{\fbox{x² \: - \: (Sum of Zeroes)x \: + \: (Product of Zeroes) \: = \: 0}}}}$

Solution :

Now find the zeroes of the above polynomial

➨ Let f(x) = x² - (13)x + 12 = 0

➨ x² - 12x - 1x + 12 = 0

➨ x(x - 12) - 1(x - 12) = 0

➨ (x - 12) ( x - 1) = 0

Substitute f(x) = 0

➨ (x - 12) ( x - 1) = 0

➨ (x - 12) = 0 or (x - 1) = 0

➨ x = 12 or x = 1