Find a quadratic polynomial whose sum and
product of zeroes are - 7 and -8 respectively. [1]
Answers
Answer:
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Answer:
x² + 7x - 8
Note:
★ The possible values of the variable for which the polynomial becomes zero are called its zeros.
★ A quadratic polynomial can have atmost two zeros.
★ To find the zeros of the given polynomial , equate it to zero .
★ If A and B are the zeros of the quadratic polynomial p(x) = ax² + bx + c , then ;
• Sum of zeros , (A+B) = -b/a
• Product of zeros , (A•B) = c/a
★ If A and B are the zeros of any quadratic polynomial , then that quadratic polynomial is given by ; x² - (A+B)x + A•B .
Solution:
Here,
It is given that , the sum and product of zeros of the required quadratic polynomial are (-7) and (-8) respectively.
Now,
Sum of zeros of required quadratic polynomial will be given as ;
A + B = -7
Also,
The product of zeros of the required quadratic polynomial will be given as ;
A•B = -8
Thus,
The required quadratic polynomial will be given as ; x² - (A+B)x + A•B
ie ; x² - (-7)x + (-8)
ie ; x² + 7x - 8