Question

Find a quadratic polynomial whose zeoes are -3 and 4

Answer 1

Answer:

x^2 - x - 12

Step-by-step explanation:

the given zeros are -3 and 4

$x = - 3 \: \: \: \: x = 4 \\ x + 3 = 0 \: \: \: x - 4 = 0 \\ multipling \: (x + 3)(x - 4) \\ = {x}^{2} - 4x + 3x - 12 \\ = {x}^{2} - x - 12 \\ \\ other \: method \\ sum \: of \: zeros \: \alpha + \beta = - 3 + 4 = 1 \\ product \: of \: zeros \: = \alpha \beta = - 3 \times 4 = - 12 \\ quadratic \: formula \\ = {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ = {x}^{2} - (1)x + ( - 12) \\ = {x}^{2} - x - 12$