find a quadratic polynomial whose zeores are -9 and 1/9
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Answer:
Quadratic polynomial=9x²+80x-9
Step-by-step explanation:
α=(-9), β=1/9
Quadratic polynomial
=x²-(α+β)x+αβ
=x²-(-9+1/9)x+(-9)(1/9)
=x²-((-81+1)/9)x+(-1)
=x²-(-80)x/9-1
=x²+80x/9-1
Multiple each term by 9
=x²×9+80x/9×9-1×9
=9x²+80x-9
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