Question

Find a quadratic polynomial whose zero are ½ and (- 3).​

Answer 1

Step-by-step explanation:

$\alpha = \frac{1}{2} \: \beta = - 3$

$required \: quadrtic \: polynomil$

$= k( {x}^{2} - ( \alpha + \beta )x + \alpha \beta )$

$= k( {x}^{2} -( \frac{1}{2} - 3)x + ( \frac{1}{2}) \times ( - 3))$

$= k( {x}^{2} - \frac{5}{2} x - \frac{3}{2} )$

$put \: k = 2$

$= \: 2( {x}^{2} + \frac{5}{2} - \frac{3}{2} )$

$= 2 {x}^{2} + 5x - 3$