Question

find a quadratic polynomial whose zero ate -3 and 5

Answer 1

Given, Zeroes : -3 and 5

Sum of zeroes = 5 + (-3)

==> sum of zeroes = 2 ...(1)

Product of zeroes = 5×-3

==> product of zeroes = -15 ...(2)

We know,

==> p(x) = x² - (sum of zeroes)x + (product of zeroes)

==> p(x) = x² - 2x - 15 { from (1) & (2) }

Hence, The required polynomial is x² - 2x - 15

Answer 2

Answer:

sum of zeroes= -3+5=2

product of zeroes=-3×5=-15

Step-by-step explanation:

quadratic polynomial is x2-2x-15

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