find a quadratic polynomial whose zeroe are 5√2 and 5-√2
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Answer:
The quadratic equation is
x^2 - 10x + 23 = 0
Step-by-step explanation:
let the general quadratic equation be
x^2 - (∆ + €)x + ∆€ = 0 ------(1)
where,
∆ = 5+√2
€ = 5-√2
∆ + € = 5 + √2 + 5 - √2
= 10 ------(2)
∆€ = (5+√2)(5-√2)
= 25-2{(a+b)(a-b)=a^2-b^2}{5^2=25,(√2)^2=2}
= 23 -------(3)
put (2),(3) in (1)
x^2 - (∆ + €)x + ∆€ = 0
x^2 - 10x + 23 = 0
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