Math, asked by shivkumar121976, 4 months ago

find a quadratic polynomial whose zeroe are 5√2 and 5-√2​

Answers

Answered by adprasad
0

Answer:

The quadratic equation is

x^2 - 10x + 23 = 0

Step-by-step explanation:

let the general quadratic equation be

x^2 - (∆ + €)x + ∆€ = 0 ------(1)

where,

∆ = 5+√2

€ = 5-√2

∆ + € = 5 + √2 + 5 - √2

= 10 ------(2)

∆€ = (5+√2)(5-√2)

= 25-2{(a+b)(a-b)=a^2-b^2}{5^2=25,(√2)^2=2}

= 23 -------(3)

put (2),(3) in (1)

x^2 - (∆ + €)x + ∆€ = 0

x^2 - 10x + 23 = 0

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