Question

Find a quadratic polynomial whose zeroes 2 + √3 , 1- 2 √3 it's urgent please do it​

Answer 1

Here is ur ans

Is it correct?

Answer 2

Let,

$\alpha = 2 + \sqrt{3} \: \: and \: \: \beta = 1 - 2 \sqrt{3}$

Then, required polynomial;

$= {x}^{2} - ( \alpha + \beta ) x \: + \alpha \beta \\ = {x}^{2} - (3 - \sqrt{3} )x + ( - 4 - 3 \sqrt{3} ) \\ = {x}^{2} - 3x - \sqrt{3} x - 4 - 3 \sqrt{3}$

The polynomial can be left in the second step or you may proceed to simplify it up to the third step.

HOPE THIS COULD HELP!!!