Question

find a quadratic polynomial whose zeroes ar i) 2/√3 and-4/√3

Answer 1

hope it helps you.......

Answer 2

Alpha=2/rooto
Beta=4/root3
Alpha+beta=
2/root3+4/root3
=6/root3
=2 root3
Now,
Alpha×beta
=2/root3×4/root3
=8/3
Now,
x^2-(alpha+beta)x+alpha×beta
=x^2-(2root3)x+8/3
=x^2-2root3x+8/3 (ans)