Question

Find a quadratic polynomial whose zeroes are 1/4,-1

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

We recall that the $a$ and $b$ are the zeroes of the quadratic polynomial,

we can written as,

$(x-a)(x-b)=0$

Given: zeroes of the quadratic polynomial are, $\frac{1}{4},-1$.

$(x-\frac{1}{4})(x-(-1))=0\\(x-\frac{1}{4})(x+1)=0\\x^2+x-\frac{1}{4}x-\frac{1}{4}=0\\x^2+\frac{3}{4}x-\frac{1}{4}=0\\4x^2+3x-1=0$