Math, asked by kavitakosi, 4 months ago

find a quadratic polynomial whose zeroes are - 11 and - 13​

Answers

Answered by Anonymous
6

Answer:

x² + 23x - 143

Step-by-step explanation:

Let,

α = - 11

β = - 13

α + β = - 11 + ( - 13 )

= - 11 - 13

α + β = - 23

αβ = - 11 ( - 13 )

αβ = 143

x² - ( α + β )x - αβ = 0

x² - ( - 23 )x - 143 = 0

x² + 23x - 143 = 0

The quadratic polynomial is x² + 23x - 143.

Answered by BoldStyle
4

α = - 11 , β = - 13

• Sum of α and β

α + β = - 11 + ( - 13 ) = - 24

• Product of α and β

αβ = - 11 x - 13 = 143

Quadratic equation :-

X² -( α + β )X + αβ = 0

X² - ( - 24 )X + 143 = 0

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X² + 24X + 143 = 0 ➡ Answer

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