find a quadratic polynomial whose zeroes are 2/3,-5/7
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Answer:
polynomial = 21x² + x - 10
Step-by-step explanation:
polynomial of form ax² + bx + c
where sum of zeroes = -b/a
product of zeroes = c/a
zeroes given = 2/3 and -5/7
Sum = 2/3 + (-5)/7 = -1/21 = -b/a
Product = 2/3 x (-5)/7 = -10/21 = c/a
a = 21 , b =1 , c = -10
polynomial = 21x² + x - 10
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