find a quadratic polynomial whose zeroes are 2/3 and -1/4
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Answered by
4
sum of zeros = 2/3-1/4=5/12
product of zero=2/3×-1/4=-2/12
polynomial formed....
x^2-5/12x-2/12
or,
12x^2-5x-2.
HOPE IT HELPS....
BRANIEST PLZZZZZZZZZ
product of zero=2/3×-1/4=-2/12
polynomial formed....
x^2-5/12x-2/12
or,
12x^2-5x-2.
HOPE IT HELPS....
BRANIEST PLZZZZZZZZZ
Answered by
6
Hi there!
The zeroes given are:
• 2/3 and • -1/4
When the zeroes are given, the formula for finding the quadratic polynomial is:
K{x² - x (sum of zeroes) + (product of zeroes)}
{ Where K is any arbitrary constant..
here,
★sum of zeroes = 2/3 + (-1/4)
= 5/12
★product of zeroes = 2/3 × -1/4
= -1/6
plug-in these values in the formula,
=> K{x² - x(5/12) + (-1/6)}
=> K{x² -5x/12 -1/6}
=> K(12x²-5x-2)/12
Put K = 12
we will get ...
the required polynomial.
i.e. 12x²-5x-2
Hope it helps!
The zeroes given are:
• 2/3 and • -1/4
When the zeroes are given, the formula for finding the quadratic polynomial is:
K{x² - x (sum of zeroes) + (product of zeroes)}
{ Where K is any arbitrary constant..
here,
★sum of zeroes = 2/3 + (-1/4)
= 5/12
★product of zeroes = 2/3 × -1/4
= -1/6
plug-in these values in the formula,
=> K{x² - x(5/12) + (-1/6)}
=> K{x² -5x/12 -1/6}
=> K(12x²-5x-2)/12
Put K = 12
we will get ...
the required polynomial.
i.e. 12x²-5x-2
Hope it helps!
AJTRIZ:
thank you so much
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