Question

find a quadratic polynomial whose zeroes are -2√3 and -√3/2

Answer 1

$\mathfrak{heya \: bro \: how \: are \: you}$

$\bold{here \: is \: your \: answer}$

$by baditya$

$let \: \alpha = - 2 \sqrt{3} \\ and \: \beta = - 3 \sqrt{2}$

$\mathfrak{and \: we \: know \: that \: the \: polynomial \: having \: \alpha and \: \beta \: as \: zero \: is \:( x - \alpha) ( x - \beta ) }$

so the polynomial is

(x+2√3)(x+√3/2)

x²+x(2√3+√3/2)+3

x²+5√3/2+3

2x²+5√3+6

hope it helps

Answer 2

Answer:

=> x² - 6x + 7

Step-by-step explanation: