find a quadratic polynomial whose zeroes are 2√3 and −5√3
Answers
Answered by
1
Hi ,
Let m , n are two zeroes of the quadratic
polynomial .
m = 2√3 , n = - 5√3 ,
i ) m + n = 2√3 - 5√3 = - 3√3
ii ) mn = ( 2√3 )( -5√3 ) = - 30
******************************
Form of a quadratic polynomial whose
zeroes are m , n
x² - ( m + n )x + mn
*******************************************
Therefore ,
Required polynomial is ,
p( x ) = x² - ( - 3√3 )x + ( - 30 )
= x² + 3√3x - 30
I hope this helps you.
: )
Let m , n are two zeroes of the quadratic
polynomial .
m = 2√3 , n = - 5√3 ,
i ) m + n = 2√3 - 5√3 = - 3√3
ii ) mn = ( 2√3 )( -5√3 ) = - 30
******************************
Form of a quadratic polynomial whose
zeroes are m , n
x² - ( m + n )x + mn
*******************************************
Therefore ,
Required polynomial is ,
p( x ) = x² - ( - 3√3 )x + ( - 30 )
= x² + 3√3x - 30
I hope this helps you.
: )
Answered by
6
Hii friend,
Let Alpha = 2✓3 and Beta = -5✓3
Sum of zeros = (Alpha + Beta) = {2✓3+(-5✓3)} => 2✓3 -5✓3 = -3✓3
And,
Product of zeros = (Alpha × Beta) = (2✓3×(-5✓3) = 2×-5 × 3 = -30
Therefore,
Required polynomial = X²-(Alpha + beta)X+ Alpha × Beta
=> X²-(3✓3)X +(-30)
=> X²-(-3✓3X)-30.
=> X²+3✓3X-30.
HOPE IT WILL HELP YOU..... :-)
Let Alpha = 2✓3 and Beta = -5✓3
Sum of zeros = (Alpha + Beta) = {2✓3+(-5✓3)} => 2✓3 -5✓3 = -3✓3
And,
Product of zeros = (Alpha × Beta) = (2✓3×(-5✓3) = 2×-5 × 3 = -30
Therefore,
Required polynomial = X²-(Alpha + beta)X+ Alpha × Beta
=> X²-(3✓3)X +(-30)
=> X²-(-3✓3X)-30.
=> X²+3✓3X-30.
HOPE IT WILL HELP YOU..... :-)
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