find a quadratic polynomial whose zeroes are 2√7 and -5√7
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Answered by
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Explanation:
f(x)=k(x^2-(sum of zeroes)x+(product of zeroes))
Sum of zeroes= 2√7 +(-5√7)
= -3√7
Product of zeroes=(2√7 )(-5√7)
= -70
so,. f(x)= k( x^2 -(-3√7)x+(-70) )
= x^2 +3√7x -70
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