Question

Find a quadratic polynomial whose zeroes are ± √3/2

Answer 1

Answer:

Given zeros of polynomial are 3±2

Let α,β be zeros of polynomial 

then

α+β=3+2+3−2=6 ________ (1)

& αβ(3+2)(3−2)

αβ=9−32+32−2=7 _________ (2)

then

quadratic equation is

x2−(α+β)x+αβ=0

From (1) & (2)

[x2−6x+7=0]

Answer 2

Answer:

Given zeros of polynomial are 3±

2

Let α,β be zeros of polynomial

then

α+β=3+

2

+3−

2

=6 ________ (1)

& αβ(3+

2

)(3−

2

)

αβ=9−3

2

+3

2

−2=7 _________ (2)

then

quadratic equation is

x

2

−(α+β)x+αβ=0

From (1) & (2)

[x

2

−6x+7=0]

Step-by-step explanation:

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