Question

Find a quadratic polynomial whose zeroes are (3 + √2) and (3 - √2)​

Answer 1

Step-by-step explanation:

alpha = (3+√2) beta (3-√2)

alpha+beta = 3+√2+3-√2

=6

alpha ×beta = (3+√2)(3-√2)

=6-3√2+3√2-2

= 4

x^2-( alpha+beta)x+alpha×beta

x^2-6x+4