Question

find a quadratic polynomial whose zeroes are 3+√2 and 3-√2​

Answer 1

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Answer 2

Step-by-step explanation:

x = 3+√2

x = 3-√2

x + 3√2 = 0

x - 3√2 = 0

0x0 = (x + 3√2) ( x-3√2)

x² - 3√2x +3√2x - 18

x² - 18 = 0