Question

Find a quadratic polynomial whose zeroes are (3+√5) and (3-√5)
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Answer 1

This is the answer
Hope this helps you
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Answer 2

Answer:

as we know

sum of zeros= -b/a

product of zeros= c/a

where a,b,c stands for

ax²+bx+c

Step-by-step explanation:

sum of zeros = 3+√5+3-√5=-6/1

product of zeros= (3+√5)×(3-√5)=3²-√5²=9-5=4/1

so equation will be 1x²-6x+4