Find a quadratic polynomial whose zeroes are -3 and 4
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Answer:
The zeroes are -3 and 4
so α = -3 and β = 4
α+β = -3+4 = 1
αβ = (-3)*4 = -12
p(x) = x²-(α+β)x+αβ
= x²-(1)x+(-12)
= x²-x-12
(OR)
zeroes are -3 and 4
so factors are (x+3) and (x-4)
p(x) = (x+3)(x-4)
= x(x-4)+3(x-4)
= x²-4x+3x-12
= x²-x-12
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