Find a quadratic polynomial whose zeroes are 3 and 4
Answers
Quadratic equation with α and β as roots can be written as
x² − ( α + b ) + αb = 0
Here,
α = −3
b = 4
∴α + b = −3 + 4 =,1
and
α − b = −3 × 4
= −12
∴ The quadratic equation is
x² − ( α + b )x + ab = 0
⇒ x²−1x−12=0
⇒ x²/2 - x/2 - 12/2 = 0
⇒ x²/2 - x/2 - 6 = 0
Hence,
The quadratic polynomial is 2x²−2x−6
EXPLANATION.
Quadratic polynomial whose zeroes are = 3 and 4.
let α and β are the zeroes of the polynomial.
sum of zeroes of quadratic polynomial,
⇒ α + β = -b/a.
⇒ -3 + 4 = 1. ........(1)
product of zeroes of quadratic polynomial.
⇒ αβ = c/a.
⇒ (-3)(4) = -12. ........(2).
quadratic polynomial whose zeroes are α and β,
⇒ x² - (α+β) + αβ.
⇒ x² - ( 1)x + (-12).
⇒ x² - x - 12 = 0.
MORE INFORMATION.
(1) = D > 0 Or b² - 4ac > 0 [ roots are real and unequal ].
(2) = D = 0 Or b² - 4ac = 0 [ roots are real and equal].
(3) = D < 0 Or b² - 4ac < 0 [ roots are imaginary ].