Question

Find a quadratic polynomial whose zeroes are -3 and 4​

Answer 1

Answer:

$\alpha = - 3 \\ \beta = 4\\ {x}^{2} -( \alpha + \beta )x + ( \alpha \beta ) \\ = > {x}^{2} - ( - 3 + 4)x + ( - 3 \times 4) \\ = > {x}^{2} - 4x - 12$

Answer 2

α=−3

β=4

x

2

−(α+β)x+(αβ)

=>x

2

−(−3+4)x+(−3×4)

=>x

2

−4x−12