find a quadratic polynomial whose zeroes are 3 and 5
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Answer: x^2 - 8x +15
Step-by-step explanation:
p(x) = ax^2 + bx + c
Zeros = 3,5
∴ x = 3, x = 5
= (x - 3)(x - 5)
= x(x - 5) - 3(x - 5)
= x^2 -5x -3x + 15
= x^2 - 8x + 15
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