Find a quadratic polynomial whose zeroes are 3 minus root 3 divided 5 and three minus root 3 divided by 5
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Alpha = 3 + ✓5 / 5 and Beta = 3 - ✓5/5
Sum of zeroes = 3 + ✓5/5 + 3 - ✓5/5
=> 3 + ✓5 + 3 - ✓5/5
=> 6 /5
And,
Product of zeroes = ( 3 + ✓5/5 × 3 - ✓5/5)
=> ( 3 + ✓5 ) ( 3 - ✓5) / 25
=> ( 3)² - (✓5)²/25
=> 9 - 5/25 = 4 /25
Therefore,
Required Quadratic polynomial = X² - ( Sum of zeroes)X + Product of zeroes
=> X² - (6/5)X + ( 4/25)
=> X² -6X/5 + 4/25
=> 25X² - 30X + 4 = 0
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