Question

find a quadratic polynomial whose zeroes are (3-root3)/5 and (3+root 3)/5

Answer 1

Let the zeroes are

$\alpha + \beta = (3 - \sqrt{3} ) \div 5$
$\alpha \beta = (3 + \sqrt{3} ) \div 5$

So quadratic polynomial is given by

$x {}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

$on \: putting \: values$

$5x {}^{2} - (3 - \sqrt{3} ) x+ (3 + \sqrt{3} ) = 0$


Thanks

Answer 2

Answer:

idk

Step-by-step explanation: