Find a quadratic polynomial whose zeroes are-4/5 and1/3
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Step-by-step explanation:
given -4/5 and 1/3 are the zeros of p(x).
we know that, sum of zero = -b/a
-4/5 - 1/3= -b/a
-12-5/ 15= -b/a
-17/15 = -b/a
also, product of zeros = c/a
( -4/ 5) * (1/3)= c/a
-4/15 = c/a
on compering it with ax^2+ bx+c
we get 15x^2+17x-4.
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