Question

find a quadratic polynomial whose zeroes are -4 and 3 and verify relationship between zeros and coefficient

Answer 1

Step-by-step explanation:

the general quadratic equation is

${x}^{2} - x( \alpha + \beta ) + \alpha \beta = 0$

where alpha,beta are the roots substitute the values and get the answer

hope this will help u

Answer 2

Answer:

Hi!!$This is Shyamini..

Step-by-step explanation:

Given,

Zeroes are -4 and 3

let -4=alpha and 3=beta

then,

sum of zeroes =-b/a

alpha+beta=b/a

_4+3= -1=-b/a

product of zeroes=c/a

alpha*beta=c/a

-4*3= -12

Quadratic formula=x2-alpha+beta x +alpha*beta=0

xsquare-(-1)x+(-12)=0

xsquare+1x-12=0

Therefor quadratic equation=

x2+x-12.

Hope this helos you...