find a quadratic polynomial whose zeroes are -4and3 & verify the relationship between
the zeroes and the coefficients.
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Answer:
1x^2+1x-12=0
Step-by-step explanation:
α=-4,ß=3
quadratic polynomial=k[x^2-(α+ß)x+α*ß]
k[x^2-(-4+3)x+(-4)(3)]
k[x^2-(-1)x-12]
k[x^2+1x-12]
kx^2+1kx-12k
if k=1->1x^2+1x-12
α+ß=-4+3/1=-1/1=-co-efficient of x/co-efficient of x^2
α*ß=-4*3=-12/1=constant/co-efficient of x^2
hope it may helps!
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