Find a quadratic polynomial whose zeroes are (5+√2) and (5-√2)
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Let us consider the quadratic equation as :
ax2+bx+c, whose roots are αβ
We know that , α+β=−b/a
and α∗β=c/a
Here, quadratic polynomial’s zeroes means its roots
so, α=5+2–√andβ=5−2–√
now, α+β=(5+2–√)+(5−2–√)=10=−ba
and, α∗β=(5+2–√)∗(5−2–√)= 23 = c/a
52−(2–√)2=25−2=23=c/a
Therefore,
ax2+bx+c=1x2−10x+23
ANS : x2−10x+23..
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