Question

Find a quadratic polynomial whose zeroes are 5-3√2 and 5+3√2.

Answer 1

Answer:

Sum of zeroes= 5-3√2+5+3√2=10

Product of zeroes= (5-3√2)(5+3√2)= 7

P(x)= X2 -10x+7

Step-by-step explanation:

Answer 2

Answer:

x^2-10x+7

Step-by-step explanation:

sum of the zeoes=5+3root+5-3root2=10

so if coefficient of x^2 is taken 1 coefficient of x is -10

product of zeroes=(5^2-(3root2)^2)

=25-18=7

so constant term is 7