Find a quadratic polynomial whose zeroes are 5-3√2 and 5+3√2.
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Answer:
x²-10x+7
Step-by-step explanation:
Sum of zeros = 5-3 root 2 + 5 + 3 root 2 = 10
Product of zeros = (5+3root2)(5-3root2)=5²-(3 root 2)² = 25-18 = 7
P(x) = x²-(sum of zeros) x + product of zeros
= x²-10x + 7
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