Question

Find a quadratic polynomial whose zeroes are 5 -3/2 and 5 +3.12.​

Answer 1

Answer:

x²-10x+97/4

Step-by-step explanation:

$\alpha + \beta = 5 - \frac{ \sqrt{3} }{2} + 5 + \frac{ \sqrt{3} }{2} \\ = 10 \\ \alpha \beta = (5 - \frac{ \sqrt{3} }{2})(5 + \frac{ \sqrt{3} }{2}) \\ = 25 - \frac{3}{4} \\ = \frac{97}{4}$