Find a quadratic polynomial, whose zeroes are 7 - 2√5 and 7 + 2√5.
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Let you know the main formula used
i.e x^2-(a+b)x+ab=0
according to the question a= (7-2√5) and b= (7+2√5)
According to above equation we get,
x^2-(7+2√5+7-2√5)x+ (7+2√5)(7-2√5)=0
x^2-14x+49-20=0
x^2-14x+29=0
i.e x^2-(a+b)x+ab=0
according to the question a= (7-2√5) and b= (7+2√5)
According to above equation we get,
x^2-(7+2√5+7-2√5)x+ (7+2√5)(7-2√5)=0
x^2-14x+49-20=0
x^2-14x+29=0
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