Question

find a quadratic polynomial whose zeroes are -9 and 1/9

Answer 1

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Answer 2

Answer:

General Form of a quadratic:

• x² - ( Sum of zeros ) x + ( Product of zeros ) = 0

Zeros : -9, 1/9

Sum of Zeros = -9 + 1/9

⇒ Sum of Zeros = -80/9

Product of Zeros = -9 × 1/9

⇒ Product of Zeros = -1

Therefore the quadratic equation can be written as:

⇒ x² - ( -80/9 ) x + ( -1 ) = 0

⇒ x² + 80x / 9 - 1 = 0

Taking LCM we get,

⇒ 9x² + 80x - 9 = 0  ( Required Quadratic Polynomial )